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SortCharactersByFrequency451.java
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71 lines (67 loc) · 1.67 KB
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/**
* Given a string, sort it in decreasing order based on the frequency of characters.
*
* Example 1:
*
* Input:
* "tree"
*
* Output:
* "eert"
*
* Explanation:
* 'e' appears twice while 'r' and 't' both appear once.
* So 'e' must appear before both 'r' and 't'. Therefore "eetr" is also a valid answer.
*
*
* Example 2:
*
* Input:
* "cccaaa"
*
* Output:
* "cccaaa"
*
* Explanation:
* Both 'c' and 'a' appear three times, so "aaaccc" is also a valid answer.
* Note that "cacaca" is incorrect, as the same characters must be together.
*
*
* Example 3:
*
* Input:
* "Aabb"
*
* Output:
* "bbAa"
*
* Explanation:
* "bbaA" is also a valid answer, but "Aabb" is incorrect.
* Note that 'A' and 'a' are treated as two different characters.
*/
public class SortCharactersByFrequency451 {
public String frequencySort(String s) {
int[] map = new int[256];
for (char c: s.toCharArray()) map[c]++;
List<Character>[] bucket = new List[s.length() + 1];
for (int i=0; i<256; i++) {
int freq = map[i];
if (freq != 0) {
if (bucket[freq] == null) bucket[freq] = new LinkedList<>();
bucket[freq].add((char) i);
}
}
StringBuilder sb = new StringBuilder();
for (int i=bucket.length-1; i>=0; i--) {
List<Character> list = bucket[i];
if (list != null) {
for (Character c: list) {
char[] chars = new char[i];
Arrays.fill(chars, c);
sb.append(chars);
}
}
}
return sb.toString();
}
}